Variable Length Subnet Mask (VLSM)

Lessons Discussion
18

Hi,

Thank you for awesome explanation. It is helping me a lot for my ccna studies

I was solving a problem as stated:-

Network ip- 172.16.0.0
No. of host needed-120

subnet mask will be 255.255.255.128
CIDR notation will be /25

so ip address range will be from 172.16.0.0 to 172.16.0.128

have I solved problem correctly.