Thanks. Sorry but Im still unclear. Your point of the 192.168 makes sense. We have a /24 but if we want to create more subnets we can use the class c range of /16 to obtain another 8 subnet bits.
However for the 172.30 address…
If wanted to create more subnets with the same amount of hosts in each, then wouldn’t we then again use the Class B range which is /12. Even if i go online it shows it being calculated the same was as you have shown. Also the binary you have shown is 172.3.x.x (?).
Thank you for all your help…