This topic is to discuss the following lesson:

Hello,

in the lesson is:

What about 10.60.0.0 /19? It falls within the 10.0.0.0 /8 range but it is not permitted because it has a subnet mask of /23â€¦our ge operator says it should be /20 or larger.

But the network has mask of /19 and not /23 so it should be â€śit has a subnet mask of /19â€¦â€ť

Hi Towdie,

You are totally right, just fixed this typo. Thanks for pointing it out!

Rene

Rene i really like the way you explain.Thank you so muchâ€¦

Yes if you use a prefix-list without GE or LE then itâ€™s just the prefix that you matched. For example, 172.16.1.0/24 is the same as 172.16.1.0 0.0.0.255 in an access-list.

Rene- Its crisp & Clear explanationâ€¦however can you help me to understand what prefixes are covered for 128.0.0.0/3 & 128.0.0.0/5â€¦?

Hi Raghav,

First you need to figure out what /3 and /5 is, write down the subnet mask:

/3 = 224.0.0.0

/5 = 248.0.0.0

A quick way to find out how many subnets are covered is by taking the number 256 and subtracting the subnet mask:

256 - 224 = 32 subnets

256 - 248 = 8 subnets

So for /3 it looks like this:

Subnet #1: 0.0.0.0/3

Subnet #2: 32.0.0.0/3

Subnet #3: 64.0.0.0/3

Subnet #4: 96.0.0.0/3

Subnet #5: 128.0.0.0/3

Subnet #6: 160.0.0.0/3

And for /5:

Subnet #1: 0.0.0.0/3

Subnet #2: 8.0.0.0/3

Subnet #3: 16.0.0.0/3

Subnet #4: 24.0.0.0/3

Subnet #5: 32.0.0.0/3

Subnet #6: 40.0.0.0/3

Subnet #7: 48.0.0.0/3

Subnet #8: 56.0.0.0/3

Subnet #9: 64.0.0.0/3

Subnet #10: 72.0.0.0/3

Subnet #11: 80.0.0.0/3

Subnet #12: 88.0.0.0/3

Subnet #13: 96.0.0.0/3

Subnet #14: 104.0.0.0/3

Subnet #15: 112.0.0.0/3

Subnet #16: 120.0.0.0/3

Subnet #17: 128.0.0.0/3

Subnet #18: 136.0.0.0/3

Subnet #19: 144.0.0.0/3

Now you can see what prefixes are covered

Rene

Thanks for this explanation. It is really clear like the rest of all the subjects you covered.

Just a quick typo, nothing seriousâ€¦

10.1.0.0/16 is permitted because itâ€™s in the 10.0.0.0/8 range and has a /16 subnet mask.

10.4.0.0/16 is permitted because itâ€™s in the 10.0.0.0/8 range and has a /19 subnet mask.

Should be a /19 instead of /16

Hi Rene,

What about route-maps lesson?. It would have been nice to know how to apply it on different cases. Just a thought.

Love your lessons. I am stick to it

Hi Alfredo,

Hmm iâ€™ll think about it. Route-maps can be used for many different things so not sure if 1 lesson with all these mixed topics would work. Here are some examples where we use route-maps:

Rene

Rene,

Do you have any video on subnetting ?

Hi Jude,

All subnetting material can be found here:

https://networklessons.com/subnetting-lessons/

Rene

Hi Rene, you explained it clearly, just one question. you said that

â€śip prefix-list NAME permit 0.0.0.0/0 le 32â€ť is like permitting all right?

is this the same with

â€śip prefix-list NAME permit 0.0.0.0/0 ge 1â€ť ?

Hi John,

Good question, itâ€™s almost the sameâ€¦the only difference is that 0.0.0.0/0 ge 1 wonâ€™t allow a default route.

The ge 1 means that the prefix should have a /1 or larger and a default route has a /0.

Rene

rene, if i have this prefix list â€ś0.0.0.0/3 ge 24â€ť, so anything on the 1st octet that is 0-31 is a valid range?

Hi John,

It means the first 3 bits of the 1st octet have to be a 0 and the subnet mask should be /24 or larger.

00000000 = 0

00011111 = 31

So yes, you are right

Rene

Hi Rene,

What is the benefit of using seq number in Prefix-List ?

Thanks.

I know this should be a clear answer, but for some reason Iâ€™m not understanding how 128.0.0.0/2 covers the whole Class B network range. If I write out 128 into decimal, it will be: I0000000. Now the mask says to match on the first two bits, so the only match would be the I0 ( I is matched and 0 is not matched?) which again equals to only the 128 network range. I would like a clear explanation on this if you may. Thanks

Hi Mario,

The first two bits have to be 10 so that means the following range is class B:

10000000 - 10111111

Or in decimal:

128 - 191

Rene