Ah, I see.
They wanted to give him a half from the 24 bits, right? Which isn’t 12 because we’re making the calculation in bits where each bit effectively doubles the MAC address count. So by removing one bit, we shrink the size by half.
David
Ah, I see.
They wanted to give him a half from the 24 bits, right? Which isn’t 12 because we’re making the calculation in bits where each bit effectively doubles the MAC address count. So by removing one bit, we shrink the size by half.
David
Hello David
Yes, that’s exactly it! That’s the nature of binary numbers. By removing the most significant bit (i.e. the leftmost bit) you essentially cut the address space in half…
Laz